24(x+3)+(x+3)^2=30x+x^2

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Solution for 24(x+3)+(x+3)^2=30x+x^2 equation:



24(x+3)+(x+3)^2=30x+x^2
We move all terms to the left:
24(x+3)+(x+3)^2-(30x+x^2)=0
We multiply parentheses
-(30x+x^2)+24x+(x+3)^2+72=0
We get rid of parentheses
-x^2-30x+24x+(x+3)^2+72=0
We add all the numbers together, and all the variables
-1x^2-6x+(x+3)^2+72=0
We move all terms containing x to the left, all other terms to the right
-1x^2-6x+(x+3)^2=-72

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